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Proof step 22 from proof nodes-no-change-eq (previous step)

gstore1[m] = groupblock(gndx0, lax0, m2), gstore0[m] = groupblock(gndx0, lax0, m3), @(m0, m1) ∈ lax0, m ∈ gstore1, m ∈ gstore0, @(m, m0, m1) ∈ nodes(gstore0, ginval) ⊦ gstore0[@(m, m0, m1)].nd = nodes(gstore1, ginval)[@(m, m0, m1)], m ∈ ginval

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
gstore0[m] = groupblock(gndx0, lax0, m3), gstore1[m] = groupblock(gndx0, lax0, m2), m ∈ gstore0, m ∈ gstore1, @(m0, m1) ∈ lax0, @(m, m0, m1) ∈ gstore0 ⊦ gstore0[@(m, m0, m1)].nd = nodes(gstore1, ginval)[@(m, m0, m1)], m ∈ ginval

Rule argument

Additional information

Used simplifier rules: nodes-gstore-in: ⊦ adr ∈ nodes(gstore, ginval) ↔ ¬ ¬(adr ∈ gstore ∧ ¬ adr.lnum ∈ ginval);% ⊦ @(m, m0, m1).lnum = m; (s)