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Proof step 7 from proof nodes-no-change-eq (previous step)

adr = @(m, m0, m1), ∀ n. (n ∈ gstore0 ↔ n ∈ gstore1) ∧ (n ∈ gstore0 → gstore1[n].gndlist = gstore0[n].gndlist ∧ gstore1[n].ladrlist = gstore0[n].ladrlist) ⊦ (¬ m ∈ ginval → (adr ∈ gstore0 ↔ adr ∈ gstore1)) ∧ (adr ∈ gstore0 ∧ ¬ m ∈ ginval → nodes(gstore0, ginval)[adr] = nodes(gstore1, ginval)[adr])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
∀ n. (n ∈ gstore0 ↔ n ∈ gstore1) ∧ (n ∈ gstore0 → gstore1[n].gndlist = gstore0[n].gndlist ∧ gstore1[n].ladrlist = gstore0[n].ladrlist) ⊦ (¬ m ∈ ginval → (@(m, m0, m1) ∈ gstore0 ↔ @(m, m0, m1) ∈ gstore1)) ∧ (@(m, m0, m1) ∈ gstore0 ∧ ¬ m ∈ ginval → nodes(gstore0, ginval)[@(m, m0, m1)] = nodes(gstore1, ginval)[@(m, m0, m1)])

Proof step 7 from proof nodes-no-change-eq (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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