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Proof step 11 from proof nodes-remove-refsize0 (previous step)

dom remove-refsize0(gstore) ∩ ginval = ∅ ⊦ (@(m, m0, m1) ∈ remove-refsize0(gstore) ↔ @(m, m0, m1) ∈ gstore ∧ ¬ m ∈ ginval ∧ gstore[m].ref-size ≠ 0) ∧ ( @(m, m0, m1) ∈ remove-refsize0(gstore) → nodes(remove-refsize0(gstore), ∅)[@(m, m0, m1)] = (nodes(gstore, ginval) \ refsize0-addresses(gstore \ ginval))[@(m, m0, m1)])

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 12:
gstore[m] = groupblock(gndx, lax, m2), dom remove-refsize0(gstore) ∩ ginval = ∅ ⊦ (@(m, m0, m1) ∈ remove-refsize0(gstore) ↔ @(m, m0, m1) ∈ gstore ∧ ¬ m ∈ ginval ∧ m2 ≠ 0) ∧ ( @(m, m0, m1) ∈ remove-refsize0(gstore) → nodes(remove-refsize0(gstore), ∅)[@(m, m0, m1)] = (nodes(gstore, ginval) \ refsize0-addresses(gstore \ ginval))[@(m, m0, m1)])

Rule argument

spec: ablock, inst: group-store name: elim seq: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m) subst: [gblock, gndx, lax, m] → [gstore[m], gndx, lax, m2]

Additional information

Used simplifier rules: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m); (elim) Used terms: gstore[m], gndx, lax, m2