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Proof step 22 from proof nodes-transaction (previous step)

# ndx = # gndx1, # lax = # gndx, # lax1 = # gndx1, gstore[n] = groupblock(gndx, lax, m), gstore[n, groupblock(gndx + gndx1, lax + lax1, m0)][@(n, m2, m3)] = mkgnode(nd, m4, boolvar, boolvar0), transaction(ndx, gndx1), @(m2, m3) ∈ lax1, n ∈ gstore ⊦ nd = ndx[pos(@(n, m2, m3), lax1.to-adr(n))], dups(lax), dups(lax + lax1), dups(lax1), n ∈ ginval

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 23:
⊦ ladr ∈ lax ↔ (∃ lax0, lax1. lax = lax0 + (ladr + lax1))
Proof step 24:
# lax1 = # gndx1, # lax = # gndx, # ndx = # gndx1, gstore[n, groupblock(gndx + gndx1, lax + lax1, m0)][@(n, m2, m3)] = mkgnode(nd, m4, boolvar, boolvar0), gstore[n] = groupblock(gndx, lax, m), transaction(ndx, gndx1), n ∈ gstore, ∃ lax0, lax2. lax1 = lax0 + (@(m2, m3) + lax2) ⊦ nd = ndx[pos(@(n, m2, m3), lax1.to-adr(n))], dups(lax1), dups(lax + lax1), dups(lax), n ∈ ginval

Rule argument

spec: list, inst: laddress-list name: in-def seq: ⊦ ladr ∈ lax ↔ (∃ lax0, lax1. lax = lax0 + (ladr + lax1)) subst: [lax, ladr] → [lax1, @(m2, m3)] flags: <all paths>

Additional information

Used terms: lax1, @(m2, m3)