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Proof step 42 from proof nodes-transaction (previous step)

# lax = # gndx, # ndx = # gndx0 + 1, # lax2 + # lax0 = # gndx0, gndx0.last = mkgnode(nd1, m1, boolvar1, true), (mkgnode(nd0, m0, true, boolvar2) ' + gndx0)[# lax2] = mkgnode(nd, m4, boolvar, boolvar0), gstore[n] = groupblock(gndx, lax, m), n ∈ gstore, ∀ n0. ¬ # gndx0 < n0 → (mkgnode(nd0, m0, true, boolvar2) ' + gndx0)[n0].nd = ndx[n0], ∀ n0. (n0 ≠ 0 ∧ ¬ # gndx0 < n0 → ¬ (mkgnode(nd0, m0, true, boolvar2) ' + gndx0)[n0].start) ∧ (n0 < # gndx0 → ¬ (mkgnode(nd0, m0, true, boolvar2) ' + gndx0)[n0].end) ⊦ gndx0 = [], nd = ndx[# lax2], dups(lax + lax2), dups(lax0), dups(lax2 + lax0), dups((lax + lax2) + lax0), dups(lax), dups(lax2), @(m2, m3) ∈ lax0, @(m2, m3) ∈ lax2, @(m2, m3) ∈ lax, n ∈ ginval

User applied rule all left

And closed the goal!

Rule argument

pos: left 8 terms: # lax2 abort: F discard: T computed: T

Additional information

Used simplifier rules: ⊦ mkgnode(nd, m, boolvar, boolvar0).nd = nd; (s)%eqle-one: ⊦ m = n + 1 ∧ n < n0 → m ≤ n0; (forward) from specification nat%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%lf-02: ⊦ m < n ∧ m = n0 → n0 < n; (forward) from specification nat-basic% ⊦ # lax = 0 ↔ lax = []; (s)% ⊦ ¬ m + n < m; (s) Used terms: # lax2