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Proof step 2 from proof prefix-append-prefix (previous step)

nx2 = nx1 + nx3, nx0 ⊑ nx1 ⊦ nx0 ⊑ nx2

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ nx ⊑ nx0 + nx1 → ¬ nx ⊑ nx0; (s)%a: ⊦ (nx + nx0) + nx1 = nx + nx0 + nx1; from specification list[nat-list-set]