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Proof step 5 from proof refsize-0-notin-index (previous step)

gstore[n] = groupblock(gndx, lax, 0), inv(gstore \ ginval), ri-cons(ri, nodes(gstore ↓, ginval)), @(n, m0, m1) ∈ ri, n ∈ gstore, ∀ n. n ∈ gstore → gstore[n].ref-size = (range ri | n).size ⊦

User applied rule all left

And obtained the following new goals

Proof step 6:
gstore[n] = groupblock(gndx, lax, 0), inv(gstore \ ginval), ri-cons(ri, nodes(gstore ↓, ginval)), n ∈ gstore, @(n, m0, m1) ∈ ri, n ∈ gstore → gstore[n].ref-size = (range ri | n).size ⊦

Rule argument

pos: left 6 terms: n abort: F discard: T computed: T

Additional information

Used terms: n