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Proof step 6 from proof refsize-nonzero-notin-ginval (previous step)

gstore[n] = groupblock(gndx, lax, m2), inv(gstore \ ginval), ri-cons(ri, nodes(gstore ↓, ginval)), n ∈ ginval, n ∈ gstore, n ∈ gstore → gstore[n].ref-size = (range ri | n).size ⊦ # ginval = 0, ginval = ∅, m2 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
gstore[adr.lnum] = groupblock(gndx, lax, (range ri | adr.lnum).size), inv(gstore \ ginval), ri-cons(ri, nodes(gstore ↓, ginval)), adr ∈ ri, adr.lnum ∈ ginval, adr.lnum ∈ gstore ⊦ # ginval = 0, ginval = ∅

Rule argument

Additional information

Used simplifier rules: size-0: ⊦ ri-cons(ri, nodes(gstore ↓, ginval)) ∧ inv(gstore \ ginval) → ((range ri | m).size = 0 ↔ ¬(∃ adr. adr ∈ range ri ∧ adr.lnum = m));% ⊦ adr ∈ range ri ↔ adr ∈ ri; (s)% ⊦ groupblock(gndx, lax, m).ref-size = m; (s)