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Proof step 3 from proof restr-empty-notin (previous step)

as | n = ∅, @(n, m0, m1) ∈ as ⊦ # as = 0, as = ∅

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ as = as0 ↔ (∀ adr. adr ∈ as ↔ adr ∈ as0)
Proof step 5:
@(n, m0, m1) ∈ as, ∀ adr. adr ∈ as | n ↔ adr ∈ ∅ ⊦ # as = 0, as = ∅

Rule argument

spec: set-basic, inst: node-store name: Extension seq: ⊦ as = as0 ↔ (∀ adr. adr ∈ as ↔ adr ∈ as0) subst: [as0, as] → [∅, as | n] flags: <all paths>

Additional information

Used terms: ∅, as | n