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Proof step 6 from proof restr-empty-notin (previous step)

@(n, m0, m1) ∈ as, ∀ adr. ¬ adr ∈ as | n ⊦ # as = 0, as = ∅

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: @(n, m0, m1)

Additional information

Used simplifier rules: ⊦ @(m, m0, m1) ∈ as | m ↔ @(m, m0, m1) ∈ as; (s) Used terms: @(n, m0, m1)