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Proof step 26 from proof size-0 (previous step)

(range ri | m).size = 0, ri[key] = @(m, m0, 0), inv(gstore \ ginval), key-cons(key, nodes(gstore ↓, ginval)[@(m, m0, 0)]), key ∈ ri, @(m0, 0) ∈ prefixn(valid-group-nodes(gstore[m].gndlist), gstore[m].ladrlist), m ∈ gstore ⊦ m ∈ ginval

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 27:
(range ri | m).size = 0, ri[key] = @(m, m0, 0), gstore[m] = groupblock(gndx, lax, m1), inv(gstore \ ginval), key-cons(key, nodes(gstore ↓, ginval)[@(m, m0, 0)]), m ∈ gstore, @(m0, 0) ∈ prefixn(valid-group-nodes(gndx), lax), key ∈ ri ⊦ m ∈ ginval

Rule argument

spec: ablock, inst: group-store name: elim seq: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m) subst: [gblock, gndx, lax, m] → [gstore[m], gndx, lax, m1]

Additional information

Used simplifier rules: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m); (elim) Used terms: gstore[m], gndx, lax, m1