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Proof step 3 from proof size-0 (previous step)

inv(gstore \ ginval), ri-cons(ri, nodes(gstore ↓, ginval)) ⊦ (range ri | m).size = 0 ↔ ¬(∃ adr. adr ∈ ri ∧ adr.lnum = m)

User applied rule case distinction

And obtained the following new goals

Proof step 4:
(range ri | m).size = 0, inv(gstore \ ginval), ri-cons(ri, nodes(gstore ↓, ginval)), ∃ adr. adr ∈ ri ∧ adr.lnum = m ⊦
Proof step 41:
inv(gstore \ ginval), ri-cons(ri, nodes(gstore ↓, ginval)) ⊦ (range ri | m).size = 0, ∃ adr. adr ∈ ri ∧ adr.lnum = m

Rule argument

pos: right 1

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