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Proof step 46 from proof size-0 (previous step)

inv(gstore \ ginval), ri-cons(ri, nodes(gstore ↓, ginval)), adr ∈ ri ⊦ #(range ri | adr.lnum) = 0, (range ri | adr.lnum).size = 0, range ri | adr.lnum = ∅, ∃ adr0. adr0 ∈ ri ∧ adr0.lnum = adr.lnum

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 47:
adr = @(m, m0, m1), inv(gstore \ ginval), ri-cons(ri, nodes(gstore ↓, ginval)), adr ∈ ri ⊦ #(range ri | m) = 0, (range ri | m).size = 0, range ri | m = ∅, ∃ adr0. adr0 ∈ ri ∧ adr0.lnum = m

Rule argument

spec: address-data name: elim seq: ⊦ (m = adr.lnum ∧ m0 = adr.pos) ∧ m1 = adr.size ↔ adr = @(m, m0, m1) subst: [adr, m, m0, m1] → [adr, m, m0, m1]

Additional information

Used simplifier rules: ⊦ (m = adr.lnum ∧ m0 = adr.pos) ∧ m1 = adr.size ↔ adr = @(m, m0, m1); (elim) Used terms: adr, m, m0, m1