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Proof step 1 from proof sub-restr-sub (conclusion)

⊦ ((ns -- n) \ ns0) -- n = (ns \ ns0) -- n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ ((ns -- n) \ ns0) -- n = (ns \ ns0) -- n, (ns -- n) \ ns0 = ns \ ns0

Rule argument

Additional information

Used simplifier rules: del-neq: ⊦ ns -- n ≠ ns0 -- n → ns ≠ ns0; (forward) from specification set-union[nat-set]