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Proof step 2 from proof abs-log-simp0 (previous step)

ax0 = ax + ax2 ⊦ ax0 = ax1 + ax2 ↔ ax = ax1

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: a: ⊦ (ax + ax0) + ax1 = ax + ax0 + ax1; from specification list[address-list-set]% ⊦ ax + ax0 = ax1 + ax0 ↔ ax = ax1; (s)