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Proof step 5 from proof inv-add3 (previous step)

jvalid ↔ jvalid2, jvalid0 ↔ jvalid4, jvalid1 ↔ jvalid3, adr = adr2, adr1 = adr3, fi = fi1, fi0 = fi2, jmaxino = jmaxino0, nd = nd2, nd1 = nd3, ndx = nd1 + nd0 + nd ', remove-refsize0(gstore0) = gstore0, elems nx ∩ jro = ∅, dom gstore0 ∪ elems nx = dom gstore ∪ jro, p_os < pmaxino, fi2.inos < jmaxino1, fi1.inos < pmaxino, inv(gstore \ jro), inv(gstore0), refsize-cons(gstore, range fi2), refsize-cons(gstore0, range fi1), ri-inj(fi2), ri-inj(fi1), pmaxino ≤ jmaxino1, fi2.lebs ⊆ dom gstore, fi1.lebs ⊆ dom gstore0, jvalid4 ∧ nx ≠ [] → valid-journal-head(nx, gstore, jro) ⊦ ⟪gjournal_journal_addn#(ndx, jvalid1, fi0, fi, gstore0, pmaxino, p_os; ax, jvalid0, jmaxino, jro, gstore, nx, jvalid; err); if err = ESUCCESS then {adr1 := ax[0]; adr0 := ax[1]; adr := ax[2]}⟫ ( (jvalid0 ∧ nx ≠ [] → valid-journal-head(nx, gstore, jro)) ∧ fi2.lebs ⊆ dom gstore ∧ refsize-cons(gstore, range fi2) ∧ inv(gstore \ jro) ∧ elems nx ∩ jro = ∅ ∧ ¬ dups(nx) ∧ dom gstore0 ∪ elems nx = dom gstore ∪ jro), pmaxino = 0, dups(nx)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
remove-refsize0(gstore0) = gstore0, elems nx ∩ jro = ∅, dom gstore0 ∪ elems nx = dom gstore ∪ jro, pmaxino ≠ 0, fi1.inos < pmaxino, fi2.inos < jmaxino1, p_os < pmaxino, inv(gstore0), inv(gstore \ jro), refsize-cons(gstore0, range fi1), refsize-cons(gstore, range fi2), ri-inj(fi1), ri-inj(fi2), pmaxino ≤ jmaxino1, fi1.lebs ⊆ dom gstore0, fi2.lebs ⊆ dom gstore, ¬ dups(nx), jvalid4 ∧ nx ≠ [] → valid-journal-head(nx, gstore, jro) ⊦ ⟪gjournal_journal_addn#(nd1 ' + nd0 ' + nd ', jvalid1, fi2, fi1, gstore0, pmaxino, p_os; ax, jvalid4, jmaxino, jro, gstore, nx, jvalid; err); if err = ESUCCESS then {adr1 := ax[0]; adr0 := ax[1]; adr := ax[2]}⟫ ( (jvalid4 ∧ nx ≠ [] → valid-journal-head(nx, gstore, jro)) ∧ fi2.lebs ⊆ dom gstore ∧ refsize-cons(gstore, range fi2) ∧ inv(gstore \ jro) ∧ elems nx ∩ jro = ∅ ∧ ¬ dups(nx) ∧ dom gstore0 ∪ elems nx = dom gstore ∪ jro)

Rule argument

Additional information

Used simplifier rules: ⊦ nd + ndx = nd ' + ndx; (s)