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Proof step 13 from proof inv-remove (previous step)

jvalid ↔ key ∈ fi, gstore = gstore1, gstore0 = gstore2, jvalid, remove-refsize0(gstore1) = gstore1, elems nx ∩ jro = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ jro, fi0.inos < pmaxino, fi.inos < jmaxino, p_os < pmaxino, inv(gstore1), inv(gstore2 \ jro), refsize-cons(gstore1, range fi0), refsize-cons(gstore2, range fi), ri-inj(fi0), ri-inj(fi), key ∈ fi, pmaxino ≤ jmaxino, fi0.lebs ⊆ dom gstore1, fi.lebs ⊆ dom gstore2, jvalid1 ∧ nx ≠ [] → valid-journal-head(nx, gstore2, jro) ⊦ [fi1 := fi -- key] ( ri-inj(fi1) → ⟪if jvalid then let n = ? in {index_get_gblock_refsize#(fi[key].lnum, fi1, fi0, jro, gstore2, gstore1, nx, pmaxino, p_os, jvalid0; ; n); index_set_gblock_refsize#(fi[key].lnum, n - fi[key].size, fi1, fi0, jro, gstore1, nx, pmaxino, p_os, jvalid0; gstore2)}⟫ ( fi1.inos < jmaxino ∧ (jvalid1 ∧ nx ≠ [] → valid-journal-head(nx, gstore2, jro)) ∧ fi1.lebs ⊆ dom gstore2 ∧ refsize-cons(gstore2, range fi1) ∧ inv(gstore2 \ jro) ∧ dom gstore1 ∪ elems nx = dom gstore2 ∪ jro)), pmaxino = 0, dups(nx)

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

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