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Proof step 29 from proof inv-remove (previous step)

jvalid ↔ jvalid0, fi2[key] = @(m, m0, m1), gstore2[m] = groupblock(gndx, lax, m2), fi = fi1, fi0 = fi2 -- key, gstore = gstore2, gstore0 = gstore1, lnum = m, n = m2 - m1, remove-refsize0(gstore1) = gstore1, elems nx ∩ jro = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ jro, fi1.inos < pmaxino, fi2.inos < jmaxino, p_os < pmaxino, inv(gstore1), inv(gstore2 \ jro), refsize-cons(gstore1, range fi1), refsize-cons(gstore2, range fi2), ri-inj(fi2), ri-inj(fi2 -- key), ri-inj(fi1), key ∈ fi2, m ∈ gstore2, pmaxino ≤ jmaxino, m2 ≥ m1, fi1.lebs ⊆ dom gstore1, fi2.lebs ⊆ dom gstore2, jvalid1 ∧ nx ≠ [] → valid-journal-head(nx, gstore2, jro) ⊦ [if lnum ∈ gstore then gstore[lnum].ref-size := n else abort] ( inv(gstore \ jro) ∧ dom gstore1 ∪ elems nx = dom gstore ∪ jro → (jvalid1 ∧ nx ≠ [] → valid-journal-head(nx, gstore, jro)) ∧ (fi2 -- key).lebs ⊆ dom gstore ∧ refsize-cons(gstore, range fi2 -- @(m, m0, m1))), pmaxino = 0, dups(nx)

Heuristic symbolic execution applied rule if positive right

And obtained the following new goals

Rule argument

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