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Proof step 45 from proof inv-remove (previous step)

gndx0.last = mkgnode(nd, m3, boolvar, false), gstore2[m, groupblock(gndx, lax, n0)][nx.last] = groupblock(gndx0, lax0, m2), gstore2[m] = groupblock(gndx, lax, n0 + m1), fi2[key] = @(m, m0, m1), remove-refsize0(gstore1) = gstore1, elems nx ∩ jro = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ jro, fi1.inos < pmaxino, fi2.inos < jmaxino, p_os < pmaxino, inv(gstore1), inv(gstore2 \ jro), inv(gstore2[m, groupblock(gndx, lax, n0)] \ jro), inv(gstore2[nx.last]), refsize-cons(gstore2, range fi2), refsize-cons(gstore1, range fi1), ri-inj(fi2), ri-inj(fi2 -- key), ri-inj(fi1), m ∈ gstore2, key ∈ fi2, nx.last ∈ gstore2[m, groupblock(gndx, lax, n0)], nx.last ∈ gstore2, pmaxino ≤ jmaxino, fi1.lebs ⊆ dom gstore1, fi2.lebs ⊆ dom gstore2, gstore2[nx.last].gndlist = [] ∨ gstore2[nx.last].gndlist.last.end ⊦ gndx0 = [], nx = [], pmaxino = 0, dups(nx), nx.last ∈ jro

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 46:
gndx0.last = mkgnode(nd, m3, boolvar, false), fi2[key] = @(m, m0, m1), gstore2[m] = groupblock(gndx, lax, n0 + m1), gstore2[m, groupblock(gndx, lax, n0)][nx.last] = groupblock(gndx0, lax0, m2), remove-refsize0(gstore1) = gstore1, elems nx ∩ jro = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ jro, p_os < pmaxino, fi2.inos < jmaxino, fi1.inos < pmaxino, inv(gstore2[nx.last]), inv(gstore2[m, groupblock(gndx, lax, n0)] \ jro), inv(gstore2 \ jro), inv(gstore1), refsize-cons(gstore1, range fi1), refsize-cons(gstore2, range fi2), ri-inj(fi1), ri-inj(fi2 -- key), ri-inj(fi2), nx.last ∈ gstore2, nx.last ∈ gstore2[m, groupblock(gndx, lax, n0)], key ∈ fi2, m ∈ gstore2, pmaxino ≤ jmaxino, fi2.lebs ⊆ dom gstore2, fi1.lebs ⊆ dom gstore1, gstore2[nx.last].gndlist = [] ∨ gstore2[nx.last].gndlist.last.end ⊦ gndx0 = [], nx = [], pmaxino = 0, dups(nx)

Rule argument

Additional information

Used simplifier rules: ⊦ elems nx ∩ ginval = ∅ ∧ nx ≠ [] → ¬ nx.last ∈ ginval; (s)%int-c: ⊦ ns ∩ ns0 = ns0 ∩ ns; from specification set-union[nat-set]%int-a: ⊦ (ns ∩ ns0) ∩ ns1 = ns ∩ ns0 ∩ ns1; from specification set-union[nat-set]