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Proof step 49 from proof inv-remove (previous step)

gndx0.last = mkgnode(nd, m3, boolvar, false), gndx1.last = mkgnode(nd0, m5, boolvar0, boolvar1), gstore2[m, groupblock(gndx, lax, n0)][nx.last] = groupblock(gndx0, lax0, m2), gstore2[m] = groupblock(gndx, lax, n0 + m1), fi2[key] = @(m, m0, m1), gstore2[nx.last] = groupblock(gndx1, lax1, m4), remove-refsize0(gstore1) = gstore1, elems nx ∩ jro = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ jro, fi1.inos < pmaxino, fi2.inos < jmaxino, p_os < pmaxino, inv(gstore1), inv(gstore2 \ jro), inv(gstore2[m, groupblock(gndx, lax, n0)] \ jro), inv(groupblock(gndx1, lax1, m4)), refsize-cons(gstore2, range fi2), refsize-cons(gstore1, range fi1), ri-inj(fi2), ri-inj(fi2 -- key), ri-inj(fi1), m ∈ gstore2, key ∈ fi2, nx.last ∈ gstore2[m, groupblock(gndx, lax, n0)], nx.last ∈ gstore2, pmaxino ≤ jmaxino, fi1.lebs ⊆ dom gstore1, fi2.lebs ⊆ dom gstore2, gndx1 = [] ∨ boolvar1 ⊦ gndx0 = [], nx = [], pmaxino = 0, dups(nx)

Heuristic nonsplitting cut applied rule cut formula

And closed the goal!

Rule argument

fma: nx.last = m

Additional information

Used simplifier rules: ⊦ n ≠ n0 → gstore[n0, gblock][n] = gstore[n]; (s)% ⊦ n ≠ n0 → (n ∈ gstore[n0, gblock] ↔ n ∈ gstore); (s)%⊦ groupblock(gndx, lax, m) = groupblock(gndx0, lax0, m0) ↔ gndx = gndx0 ∧ lax = lax0 ∧ m = m0; (ws)%⊦ mkgnode(nd, m, boolvar, boolvar0) = mkgnode(nd0, m0, boolvar1, boolvar2) ↔ nd = nd0 ∧ m = m0 ∧ (boolvar ↔ boolvar1) ∧ (boolvar0 ↔ boolvar2); (ws)% ⊦ gstore[n, gblock][n] = gblock; (s)% ⊦ n ∈ gstore[n, gblock]; (s)%lebs-in-ri-in-gstore-explicit: ⊦ key ∈ ri ∧ ri[key] = adr ∧ ri.lebs ⊆ dom gstore → adr.lnum ∈ gstore; (forward) from specification gjournal-base% ⊦ @(m, m0, m1).lnum = m; (s) Used formulas: nx.last = m