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Proof step 152 from proof inv-store (previous step)

gstore3[m0] = groupblock(gndx, lax, m3), gstore3[@(m0, m1, m2)] = mkgnode(nd, m, boolvar, boolvar0), remove-refsize0(gstore2) = gstore2, elems nx ∩ jro0 = ∅, dom gstore2 ∪ elems nx = dom gstore3 ∪ jro0, fi1.inos < pmaxino, fi2.inos < jmaxino, p_os < pmaxino, jro1 < jmaxino, inv(gstore2), inv(gstore3 \ jro0), inv(gstore3[m0, groupblock(gndx, lax, m3 + m2)] \ jro0), key-cons(key, nd), refsize-cons(gstore2, range fi1), refsize-cons(gstore3, range fi2), ri-inj(fi1), ri-inj(fi2[key, @(m0, m1, m2)]), ri-inj(fi2), @(m0, m1, m2) ∈ gstore3, m0 ∈ gstore3, pmaxino ≤ jmaxino, pmaxino ≤ max(key.ino + 1, jmaxino), fi1.lebs ⊆ dom gstore2, fi2.lebs ⊆ dom gstore3, jvalid1 ∧ nx ≠ [] → valid-journal-head(nx, gstore3, jro0) ⊦ jmaxino = 0, max(key.ino + 1, jmaxino) = 0, pmaxino = 0, fi2.inos ∪ (key.inode? ⊃ ∅ ++ key.ino;∅) < max(key.ino + 1, jmaxino), dups(nx), key ∈ fi2, @(m0, m1, m2) ∈ fi2

Heuristic nonsplitting cut applied rule cut formula

And closed the goal!

Rule argument

fma: key.inode?

Additional information

Used simplifier rules: ⊦ ns ∪ ∅ = ns; (s)%una: ⊦ (ns ∪ ns0) ∪ ns1 = ns ∪ ns0 ∪ ns1; from specification set-union[nat-set]%unc: ⊦ ns ∪ ns0 = ns0 ∪ ns; from specification set-union[nat-set]% ⊦ ns < n → ns < max(m + 1, n); (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic% ⊦ (ns ++ n) ∪ ns0 = (ns ∪ ns0) ++ n; (s)% ⊦ ns < n → ns ++ m < max(m + 1, n); (s) Used formulas: key.inode?