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Proof step 74 from proof inv-store (previous step)

gstore3[m3] = groupblock(gndx, lax, n1 + m5), fi2[key] = @(m3, m4, m5), gstore3[@(m0, m1, m2)] = mkgnode(nd, m, boolvar, boolvar0), gstore3[m3, groupblock(gndx, lax, n1)][m0] = groupblock(gndx0, lax0, m6), gstore3[m0] = groupblock(gndx2, lax2, (range fi2 | m0).size), remove-refsize0(gstore2) = gstore2, elems nx ∩ jro0 = ∅, dom gstore2 ∪ elems nx = dom gstore3 ∪ jro0, fi1.inos < pmaxino, fi2.inos < jmaxino, p_os < pmaxino, jro1 < jmaxino, inv(gstore3[m3, groupblock(gndx, lax, n1)] \ jro0), inv(gstore2), inv(gstore3 \ jro0), inv(gstore3[m3, groupblock(gndx, lax, n1)][m0, groupblock(gndx0, lax0, m6 + m2)] \ jro0), key-cons(key, nd), refsize-cons(gstore2, range fi1), ri-inj(fi1), ri-inj(fi2[key, @(m0, m1, m2)]), ri-inj(fi2), m0 ∈ gstore3, m0 ∈ gstore3[m3, groupblock(gndx, lax, n1)], @(m0, m1, m2) ∈ gstore3, key ∈ fi2, m3 ∈ gstore3, m0 ∈ dom gstore3 ∪ jro0, pmaxino ≤ jmaxino, pmaxino ≤ max(key.ino + 1, jmaxino), fi1.lebs ⊆ dom gstore2, fi2.lebs ⊆ dom gstore3, jvalid1 ∧ nx ≠ [] → valid-journal-head(nx, gstore3, jro0) ⊦ #(dom gstore3 ∪ jro0) = 0, jmaxino = 0, m6 = ((range fi2 -- @(m3, m4, m5)) | m0).size, max(key.ino + 1, jmaxino) = 0, pmaxino = 0, dom gstore3 ∪ jro0 = ∅, dups(nx), @(m0, m1, m2) ∈ fi2

Heuristic nonsplitting cut applied rule cut formula

And closed the goal!

Rule argument

fma: m0 = m3

Additional information

Used simplifier rules: ⊦ n ≠ n0 → gstore[n0, gblock][n] = gstore[n]; (s)% ⊦ m ≠ n → (as -- @(m, m0, m1)) | n = as | n; (s)% ⊦ n ≠ n0 → (n ∈ gstore[n0, gblock] ↔ n ∈ gstore); (s)%⊦ groupblock(gndx, lax, m) = groupblock(gndx0, lax0, m0) ↔ gndx = gndx0 ∧ lax = lax0 ∧ m = m0; (ws)% ⊦ gstore[n, gblock][n] = gblock; (s)% ⊦ (as -- @(m, m0, m1)) | m = (as | m) -- @(m, m0, m1); (s)% ⊦ (as -- adr).size = as.size - (adr ∈ as ⊃ adr.size;0); (s)% ⊦ @(m, m0, m1) ∈ as | m ↔ @(m, m0, m1) ∈ as; (s)% ⊦ key ∈ ri ∧ ri[key] = adr → adr ∈ range ri; (ss)% ⊦ @(m, m0, m1).size = m1; (s)% ⊦ n ∈ gstore[n, gblock]; (s)% ⊦ gstore[n, gblock][n, gblock0] = gstore[n, gblock0]; (s)% ⊦ m + n - m = n; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic Used formulas: m0 = m3