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Proof step 2 from proof ls-inv-prefix-app-prefixn (previous step)

# lax1 < # gndx1, inv(groupblock(gndx0 + prefixn(# lax1, gndx1), lax0 + lax1, m)) ⊦ prefixn(# gndx0, lax0 + lax) = lax0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
# lax1 < # gndx1, inv(groupblock(gndx0 + prefixn(# lax1, gndx1), lax0 + lax1, m)) ⊦ gndx1 = [], prefixn(# gndx0, lax0 + lax) = lax0

Rule argument

Additional information

Used simplifier rules: ⊦ # gndx = 0 ↔ gndx = []; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic