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Proof step 26 from proof term-remove-nonend-blocks (previous step)

jvalid1 ↔ false, jvalid ↔ jvalid0, ax = ax0 + gstore2[n].ladrlist.to-adr(n), err = err0, err = ESUCCESS, gndx = gndx1, gndx0 = [], gndx2 = gndx0 + gstore2[n].gndlist, ¬ jvalid, log0 = ax, inv(gstore2), n ∈ gstore2, # gndx ≤ # log, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪gndx := gndx.butlast⟫ ((# gndx ≤ # log.butlast ∧ inv(gstore2)) ∧ (jvalid ⊃ 0;# gndx) < (jvalid0 ⊃ 0;# gndx1)), gndx = [], log = [], gndx.last.end, n ∈ ginval

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ ⌊ESUCCESS⌋ ; (s)% ⊦ gndx ≠ [] → # gndx.butlast = # gndx - 1; (s)% ⊦ ax ≠ [] → # ax.butlast = # ax - 1; (s)% ⊦ m ≤ n ↔ ¬ n < m; (ss)% ⊦ m < 1 ↔ m = 0; (s)% ⊦ # gndx = 0 ↔ gndx = []; (s)%n0 ≤ n ⊦ n - n0 ≤ m ↔ n ≤ m + n0; (s)%n0 ≤ n ⊦ n - n0 < m ↔ n < m + n0; (s)% ⊦ m < n + 1 ↔ ¬ n < m; (s)% ⊦ ¬ n < n; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat% ⊦ ¬ n + (m - n) < m; (s)