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Proof step 7 from proof term-restore-log (previous step)

elems nx3 ∩ ginval = ∅, elems nx2 ∩ ginval = ∅, nx3 ≠ [], inv(gstore2), elems nx3 ⊆ dom gstore2, elems nx2 ⊆ dom gstore2 ⊦ ⟪gjournal_remove_nonend_blocks#(nx3.head, fi0, fi, ginval, gstore2, gstore, nx, pmaxino, p_os, jvalid; log; err); nx0 := nx3.tail⟫ (elems nx0 ⊆ dom gstore2 ∧ elems nx0 ∩ ginval = ∅ ∧ # nx0 < # nx3)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 8:
nx3 = n + nx1, elems nx2 ∩ ginval = ∅, elems nx3 ∩ ginval = ∅, inv(gstore2), elems nx2 ⊆ dom gstore2, elems nx3 ⊆ dom gstore2 ⊦ ⟪gjournal_remove_nonend_blocks#(n, fi0, fi, ginval, gstore2, gstore, nx, pmaxino, p_os, jvalid; log; err); nx0 := nx1⟫ (elems nx0 ⊆ dom gstore2 ∧ elems nx0 ∩ ginval = ∅ ∧ # nx0 < # nx3), nx3 = []

Rule argument

spec: list-data, inst: nat-list-set name: elim-list-c seq: nx ≠ [] ⊦ n = nx.head ∧ nx0 = nx.tail ↔ nx = n + nx0 subst: [nx, n, nx0] → [nx3, n, nx1]

Additional information

Used simplifier rules: nx ≠ [] ⊦ n = nx.head ∧ nx0 = nx.tail ↔ nx = n + nx0; (elim) Used terms: nx3, n, nx1