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Proof step 3 from proof at-write-at (previous step)

# ax = # ndx, adr ∈ ax ⊦ fs[ax, ndx][adr] = ndx[pos(adr, ax)], dups(ax)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ adr ∈ ax ↔ (∃ ax0, ax1. ax = ax0 + (adr + ax1))
Proof step 5:
# ax = # ndx, ∃ ax0, ax1. ax = ax0 + (adr + ax1) ⊦ fs[ax, ndx][adr] = ndx[pos(adr, ax)], dups(ax)

Rule argument

spec: list, inst: address-list-set name: in-def seq: ⊦ adr ∈ ax ↔ (∃ ax0, ax1. ax = ax0 + (adr + ax1)) subst: [ax, adr] → [ax, adr] flags: <all paths>

Additional information

Used terms: ax, adr