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Proof step 2 from proof flashsize-app (previous step)

∀ ndx1. (ndx + ndx1).flashsize = ndx.flashsize + ndx1.flashsize ⊦ ((nd + ndx) + ndx1).flashsize = (nd + ndx).flashsize + ndx1.flashsize

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
∀ ndx1. (ndx + ndx1).flashsize = ndx.flashsize + ndx1.flashsize ⊦ (ndx + ndx1).flashsize = ndx.flashsize + ndx1.flashsize

Rule argument

Additional information

Used simplifier rules: flashsize-nodes-rec: ⊦ (nd ' + ndx).flashsize = nd.flashsize + ndx.flashsize;%c: ⊦ m + n = n + m; from specification nat-basic% ⊦ m + n = m + n0 ↔ n = n0; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%a: ⊦ (ndx + ndx0) + ndx1 = ndx + ndx0 + ndx1; from specification list[node-list]% ⊦ nd + ndx = nd ' + ndx; (s)