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Proof step 17 from proof index-update-range (previous step)

# kx0 = # ax0, range ri ∩ ax0.toSet = ∅, ri-inj(ri), key ∈ ri, kx0.toSet ⊆ dom ri, range ri[kx0, ax0] = (range ri \ ri[kx0].toSet) ∪ ax0.toSet ∨ dups(kx0) ∨ dups(ax0), ∀ kx1, ax, ri. # kx1 < #(kx0 + key ') → # kx1 = # ax ∧ ax.toSet ∩ range ri = ∅ ∧ ri-inj(ri) ∧ kx1.toSet ⊆ dom ri → range ri[kx1, ax] = (range ri \ ri[kx1].toSet) ∪ ax.toSet ∨ dups(kx1) ∨ dups(ax) ⊦ (range ri[kx0, ax0] -- ri[key]) ++ adr = (ax0.toSet ∪ ((range ri \ ri[kx0].toSet) -- ri[key])) ++ adr, dups(ax0), dups(kx0), adr ∈ ax0, key ∈ kx0, adr ∈ ri

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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