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Proof step 1 from proof key-cons-app (conclusion)
⊦ key-cons(ndx0 + ndx1) ↔ key-cons(ndx0) ∧ key-cons(ndx1)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
⊦ key-cons(ndx0 + ndx1) ↔ key-cons(ndx0) ∧ key-cons(ndx1)
Rule argument
Additional information