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Proof step 2 from proof keys-in (previous step)

key ∈ ns.keys ⊦ # ns.keys = 0, ns.keys = ∅, ∃ n. key = inodekey(n) ∧ n ∈ ns

User applied rule apply lemma

And obtained the following new goals

Proof step 3:
⊦ ns.keys.inodes?
Proof step 4:
ns.keys.inodes?, key ∈ ns.keys ⊦ # ns.keys = 0, ns.keys = ∅, ∃ n. key = inodekey(n) ∧ n ∈ ns

Rule argument

spec: <toplevel> name: keys-inodekeys seq: ⊦ ns.keys.inodes? subst: [ns] → [ns]

Additional information

Used terms: ns