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Proof step 14 from proof keys-inodekeys (previous step)

∀ ns1. # ns1 < #(ns0 ++ n) → true → ns1.keys.inodes? ⊦ (ns0.keys ++ inodekey(n)).inodes?, ns0.keys.inodes?, n ∈ ns0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information