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Proof step 9 from proof lebs-in-ri-in-gstore-explicit (previous step)

ri[key] = @(m, m0, m1), key ∈ ri ⊦ m ∈ gstore, ∃ adr. adr.lnum = m ∧ adr ∈ ri

User applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: @(m, m0, m1) abort: F discard: T computed: F

Additional information

Used simplifier rules: in-data-explicit: ⊦ key ∈ ri ∧ ri[key] = adr → adr ∈ ri;% ⊦ @(m, m0, m1).lnum = m; (s) Used terms: @(m, m0, m1)