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Proof step 13 from proof lebs-lookup-subseteq (previous step)

@(m, m0, m1) ∈ ri[ks] ⊦ # ri[ks] = 0, ri[ks] = ∅, m ∈ ns, ri[ks].lebs ⊆ ri.lebs, ∃ adr. adr.lnum = m ∧ adr ∈ ri

User applied rule exists right

And obtained the following new goals

Proof step 14:
@(m, m0, m1) ∈ ri[ks] ⊦ # ri[ks] = 0, ri[ks] = ∅, m ∈ ns, ri[ks].lebs ⊆ ri.lebs, @(m, m0, m1).lnum = m ∧ @(m, m0, m1) ∈ ri

Rule argument

pos: right 5 terms: @(m, m0, m1) abort: F discard: T computed: T

Additional information

Used terms: @(m, m0, m1)