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Proof step 6 from proof lebs-lookup-subseteq (previous step)

adr ∈ ri[ks], ri.lebs ⊆ ns ⊦ # ri[ks] = 0, ri[ks] = ∅, adr.lnum ∈ ns, ri[ks].lebs ⊆ ri.lebs

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 7:
adr = @(m, m0, m1), adr ∈ ri[ks], ri.lebs ⊆ ns ⊦ # ri[ks] = 0, ri[ks] = ∅, m ∈ ns, ri[ks].lebs ⊆ ri.lebs

Rule argument

spec: address-data name: elim seq: ⊦ (m = adr.lnum ∧ m0 = adr.pos) ∧ m1 = adr.size ↔ adr = @(m, m0, m1) subst: [adr, m, m0, m1] → [adr, m, m0, m1]

Additional information

Used simplifier rules: ⊦ (m = adr.lnum ∧ m0 = adr.pos) ∧ m1 = adr.size ↔ adr = @(m, m0, m1); (elim) Used terms: adr, m, m0, m1