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Proof step 10 from proof lebs-rem-subseteq (previous step)

@(m, m0, m1) ∈ ri \ ks, ∀ n. n ∈ ri.lebs → n ∈ ns ⊦ m ∈ ns, (ri \ ks).lebs ⊆ ri.lebs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
@(m, m0, m1) ∈ ri \ ks, ∀ n. (∃ adr. adr.lnum = n ∧ adr ∈ ri) → n ∈ ns ⊦ m ∈ ns, (ri \ ks).lebs ⊆ ri.lebs

Rule argument

Additional information

Used simplifier rules: lebs-index: ⊦ n ∈ ri.lebs ↔ (∃ adr. adr.lnum = n ∧ adr ∈ ri);