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Proof step 11 from proof lebs-write-subseteq0 (previous step)

@(m0, m3, m4) ∈ ri[key, @(m, m1, m2)], m ∈ gstore, ∀ n. (∃ adr. adr.lnum = n ∧ adr ∈ ri) → n ∈ gstore ⊦ m0 ∈ gstore, ri[key, @(m, m1, m2)].lebs ⊆ ri.lebs

User applied rule all left

And obtained the following new goals

Proof step 12:
m ∈ gstore, @(m0, m3, m4) ∈ ri[key, @(m, m1, m2)], (∃ adr. adr.lnum = m0 ∧ adr ∈ ri) → m0 ∈ gstore ⊦ m0 ∈ gstore, ri[key, @(m, m1, m2)].lebs ⊆ ri.lebs

Rule argument

pos: left 3 terms: m0 abort: F discard: T computed: T

Additional information

Used terms: m0