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Proof step 16 from proof lebs-write-subseteq0 (previous step)

@(m0, m3, m4) ∈ ri[key, @(m, m1, m2)], m ∈ gstore ⊦ m0 ∈ gstore, ri[key, @(m, m1, m2)].lebs ⊆ ri.lebs, ∃ adr. adr.lnum = m0 ∧ adr ∈ ri, @(m0, m3, m4) ≠ @(m, m1, m2) ∧ ¬ @(m0, m3, m4) ∈ ri

User applied rule case distinction

And obtained the following new goals

Proof step 17:
@(m0, m3, m4) ∈ ri, m ∈ gstore, @(m0, m3, m4) ∈ ri[key, @(m, m1, m2)] ⊦ m0 ∈ gstore, ri[key, @(m, m1, m2)].lebs ⊆ ri.lebs, ∃ adr. adr.lnum = m0 ∧ adr ∈ ri

Rule argument

pos: right 4

Additional information

Used simplifier rules: ⊦ @(m, m0, m1) = @(m2, m3, m4) ↔ m = m2 ∧ m0 = m3 ∧ m1 = m4; (ws)