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Proof step 6 from proof lebs-write-subseteq0 (previous step)

adr ∈ ri[key, @(m, m1, m2)], m ∈ gstore, ri.lebs ⊆ dom gstore ⊦ adr.lnum ∈ gstore, ri[key, @(m, m1, m2)].lebs ⊆ ri.lebs

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 7:
adr = @(m0, m3, m4), m ∈ gstore, adr ∈ ri[key, @(m, m1, m2)], ri.lebs ⊆ dom gstore ⊦ m0 ∈ gstore, ri[key, @(m, m1, m2)].lebs ⊆ ri.lebs

Rule argument

spec: address-data name: elim seq: ⊦ (m = adr.lnum ∧ m0 = adr.pos) ∧ m1 = adr.size ↔ adr = @(m, m0, m1) subst: [adr, m, m0, m1] → [adr, m0, m3, m4]

Additional information

Used simplifier rules: ⊦ (m = adr.lnum ∧ m0 = adr.pos) ∧ m1 = adr.size ↔ adr = @(m, m0, m1); (elim) Used terms: adr, m0, m3, m4