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Proof step 11 from proof lebs-write (previous step)

@(m2, m3, m4) ∈ ri[key, @(m, m0, m1)] ⊦ m2 = m, key ∈ ri, ∃ adr0. adr0.lnum = m2 ∧ adr0 ∈ ri

User applied rule exists right

And closed the goal!

Rule argument

pos: right 3 terms: @(m2, m3, m4) abort: F discard: T computed: F

Additional information

Used simplifier rules: ⊦ @(m, m0, m1).lnum = m; (s)% ⊦ ¬ key ∈ ri → (adr ∈ ri[key, adr0] ↔ adr ∈ ri ∨ adr = adr0); (ws)% ⊦ @(m, m0, m1) = @(m2, m3, m4) ↔ m = m2 ∧ m0 = m3 ∧ m1 = m4; (ws) Used terms: @(m2, m3, m4)