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Proof step 22 from proof lebs-write (previous step)

ri[key0] = @(n, m3, m4), key0 ∈ ri ⊦ key ∈ ri, ∃ adr. adr.lnum = n ∧ adr ∈ ri[key, @(m, m0, m1)]

User applied rule exists right

And obtained the following new goals

Proof step 23:
ri[key0] = @(n, m3, m4), key0 ∈ ri ⊦ key ∈ ri, ∃ adr. adr.lnum = n ∧ adr ∈ ri[key, @(m, m0, m1)], @(m, m0, m1).lnum = n ∧ @(m, m0, m1) ∈ ri[key, @(m, m0, m1)]

Rule argument

pos: right 2 terms: @(m, m0, m1) abort: F discard: F computed: T

Additional information

Used terms: @(m, m0, m1)