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Proof step 2 from proof new-inter-empty (previous step)

new(ax, fs), as ⊆ dom fs ⊦ ax.toSet ∩ as = ∅

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
new(ax, fs), as ⊆ dom fs ⊦ #(ax.toSet ∩ as) = 0, ax.toSet ∩ as = ∅

Rule argument

Additional information

Used simplifier rules: size-zero: ⊦ # as ≠ 0 → as ≠ ∅; (forward) from specification set-basic[node-store]%size-zero-01: ⊦ as ≠ ∅ → # as ≠ 0; (forward) from specification set-basic[node-store]