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Proof step 14 from proof nodes-cons-rec (previous step)

# ax = # ndx, gstore[@(m, m0, m1)] = mkgnode(nd0, m2, boolvar, boolvar0), ax[n] = @(m3, m4, m5), gstore[@(m3, m4, m5)] = mkgnode(nd1, m6, boolvar1, boolvar2), ∀ n. ¬ # ndx < n → (@(m, m0, m1) ' + ax)[n] ∈ gstore ∧ ¬ (@(m, m0, m1) ' + ax)[n].lnum ∈ ginval ∧ gstore[(@(m, m0, m1) ' + ax)[n]].nd = (nd ' + ndx)[n] ⊦ @(m, m0, m1) ∈ gstore ∧ ¬ m ∈ ginval ∧ nd0 = nd ∧ (n < # ndx → @(m3, m4, m5) ∈ gstore ∧ ¬ m3 ∈ ginval ∧ nd1 = ndx[n])

User applied rule all left

And obtained the following new goals

Proof step 15:
# ax = # ndx, gstore[@(m3, m4, m5)] = mkgnode(nd1, m6, boolvar1, boolvar2), ax[n] = @(m3, m4, m5), gstore[@(m, m0, m1)] = mkgnode(nd0, m2, boolvar, boolvar0), ¬ # ndx < 0 → (@(m, m0, m1) ' + ax)[0] ∈ gstore ∧ ¬ (@(m, m0, m1) ' + ax)[0].lnum ∈ ginval ∧ gstore[(@(m, m0, m1) ' + ax)[0]].nd = (nd ' + ndx)[0], ∀ n. ¬ # ndx < n → (@(m, m0, m1) ' + ax)[n] ∈ gstore ∧ ¬ (@(m, m0, m1) ' + ax)[n].lnum ∈ ginval ∧ gstore[(@(m, m0, m1) ' + ax)[n]].nd = (nd ' + ndx)[n] ⊦ @(m, m0, m1) ∈ gstore ∧ ¬ m ∈ ginval ∧ nd0 = nd ∧ (n < # ndx → @(m3, m4, m5) ∈ gstore ∧ ¬ m3 ∈ ginval ∧ nd1 = ndx[n])

Rule argument

pos: left 5 terms: 0 abort: F discard: F computed: T

Additional information

Used terms: 0