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Proof step 3 from proof nodes-cons-write-other (previous step)

# ax = # ndx, gblock.gndlist = gstore[n].gndlist, gblock.ladrlist = gstore[n].ladrlist, n0 < # ndx, ∀ n. n < # ndx → ax[n] ∈ gstore ∧ ¬ ax[n].lnum ∈ ginval ∧ gstore[ax[n]].nd = ndx[n] ⊦ ndx = [], ax[n0] ∈ gstore[n, gblock] ∧ ¬ ax[n0].lnum ∈ ginval ∧ gstore[n, gblock][ax[n0]].nd = ndx[n0]

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
# ax = # ndx, gblock = groupblock(gndx, lax, m), gndx = gstore[n].gndlist, lax = gstore[n].ladrlist, n0 < # ndx, ∀ n. n < # ndx → ax[n] ∈ gstore ∧ ¬ ax[n].lnum ∈ ginval ∧ gstore[ax[n]].nd = ndx[n] ⊦ ndx = [], ax[n0] ∈ gstore[n, gblock] ∧ ¬ ax[n0].lnum ∈ ginval ∧ gstore[n, gblock][ax[n0]].nd = ndx[n0]

Rule argument

spec: ablock, inst: group-store name: elim seq: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m) subst: [gblock, gndx, lax, m] → [gblock, gndx, lax, m]

Additional information

Used simplifier rules: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m); (elim) Used terms: gblock, gndx, lax, m