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Proof step 21 from proof range-write-in (previous step)

key ∈ ri, ∀ key0, key1. key0 ∈ ri ∧ key1 ∈ ri ∧ ri[key0] = ri[key1] → key0 = key1, adr0 = adr ∨ adr0 ≠ ri[key] ∧ (∃ key. key ∈ ri ∧ ri[key] = adr0) ⊦ ∃ key0. key0 ∈ ri[key, adr] ∧ ri[key, adr][key0] = adr0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
key ∈ ri, ∀ key0, key1. key0 ∈ ri ∧ key1 ∈ ri ∧ ri[key0] = ri[key1] → key0 = key1, adr0 = adr ∨ ri[key0] ≠ ri[key] ∧ key0 ∈ ri ∧ ri[key0] = adr0 ⊦ ∃ key0. key0 ∈ ri[key, adr] ∧ ri[key, adr][key0] = adr0

Proof step 21 from proof range-write-in (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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