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Proof step 5 from proof referenced-adrs-eq-one-lookup (previous step)

referenced-adrs(ax1, ri) = [], referenced-adrs(ax0, ri) = [], adr ∈ ri ⊦ ∃ ax, ax2. ax0 + adr ' + ax1 = ax + adr ' + ax2 ∧ referenced-adrs(ax, ri) = [] ∧ referenced-adrs(ax2, ri) = []

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: ax0, ax1

Additional information

Used simplifier rules: a: ⊦ (ax + ax0) + ax1 = ax + ax0 + ax1; from specification list[address-list-set] Used terms: ax0, ax1