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Proof step 19 from proof referenced-adrs-in (previous step)

adr ∈ ax0, adr ∈ referenced-adrs(ax0, ri), ∀ adr, ri. adr ∈ referenced-adrs(ax0, ri) ↔ adr ∈ ax0 ∧ adr ∈ ri ⊦ adr0 ∈ ri, adr ∈ ri

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: adr, ri

Additional information

Used terms: adr, ri