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Proof step 3 from proof referenced-adrs-inter-empty (previous step)

ax.toSet ∩ as = ∅ ⊦ #(referenced-adrs(ax, ri).toSet ∩ as) = 0, referenced-adrs(ax, ri).toSet ∩ as = ∅

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ as = as0 ↔ (∀ adr. adr ∈ as ↔ adr ∈ as0)
Proof step 5:
ax.toSet ∩ as = ∅ ⊦ #(referenced-adrs(ax, ri).toSet ∩ as) = 0, ∀ adr. adr ∈ referenced-adrs(ax, ri).toSet ∩ as ↔ adr ∈ ∅

Rule argument

spec: set-basic, inst: node-store name: Extension seq: ⊦ as = as0 ↔ (∀ adr. adr ∈ as ↔ adr ∈ as0) subst: [as0, as] → [∅, referenced-adrs(ax, ri).toSet ∩ as] flags: <all paths>

Additional information

Used terms: ∅, referenced-adrs(ax, ri).toSet ∩ as