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Proof step 9 from proof referenced-adrs-inter-empty (previous step)

adr ∈ ri, adr ∈ ax, adr ∈ as, ∀ adr0. ¬ adr0 ∈ ax.toSet ∩ as ⊦ #(referenced-adrs(ax, ri).toSet ∩ as) = 0, # as = 0, as = ∅

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: adr

Additional information

Used simplifier rules: ⊦ adr ∈ as ∩ as0 ↔ adr ∈ as ∧ adr ∈ as0; (ws)% ⊦ adr ∈ ax.toSet ↔ adr ∈ ax; (s)%int-a: ⊦ (as ∩ as0) ∩ as1 = as ∩ as0 ∩ as1; from specification set-union[node-store]%int-c: ⊦ as ∩ as0 = as0 ∩ as; from specification set-union[node-store] Used terms: adr