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Proof step 5 from proof referenced-adrs-lookup-key-cons (previous step)

ri-cons(ri, fs), ∀ ri, fs. ri-cons(ri, fs) → key-cons(fs[referenced-adrs(ax0, ri)]) ⊦ key-cons(fs[(adr ∈ ri ⊃ adr ';[])]) ∧ key-cons(fs[referenced-adrs(ax0, ri)])

User applied rule all left

And obtained the following new goals

Proof step 6:
ri-cons(ri, fs), ri-cons(ri, fs) → key-cons(fs[referenced-adrs(ax0, ri)]) ⊦ key-cons(fs[(adr ∈ ri ⊃ adr ';[])]) ∧ key-cons(fs[referenced-adrs(ax0, ri)])

Rule argument

pos: left 2 terms: ri, fs abort: F discard: T computed: T

Additional information

Used terms: ri, fs