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Proof step 16 from proof referenced-adrs-lookup-keys-nodups (
previous step
)
⊦ fs[ax] = ndx0 + ndx1 ↔ (∃ ax0, ax1. ax = ax0 + ax1 ∧ fs[ax0] = ndx0 ∧ fs[ax1] = ndx1)
A spec-lemma